daveinspain Posted April 21, 2013 Share Posted April 21, 2013 I've been sunning my 2007 les Paul cherry bust in hopes to tone it down a bit, color wise.... Will leaving it in the sun do this? Seem I remember someone posting that the newer finishes are mostly plastic... :blink: If so will the sun still fade it? Link to comment Share on other sites More sharing options...
AXE® Posted April 21, 2013 Share Posted April 21, 2013 It will take a LONG time. And if the pickups are potted... They may melt. Link to comment Share on other sites More sharing options...
Riffster Posted April 21, 2013 Share Posted April 21, 2013 Be careful with the fretbaord too, it will lighten up fast. Link to comment Share on other sites More sharing options...
AXE® Posted April 21, 2013 Share Posted April 21, 2013 And the inlays may curl and fall out. Link to comment Share on other sites More sharing options...
daveinspain Posted April 21, 2013 Author Share Posted April 21, 2013 Link to comment Share on other sites More sharing options...
daveinspain Posted April 21, 2013 Author Share Posted April 21, 2013 I'll cover the neck... Link to comment Share on other sites More sharing options...
Guest Farnsbarns Posted April 21, 2013 Share Posted April 21, 2013 Find a UV cannon somewhere (local college/university???). You can hit it with years worth of sun in seconds. The great Gil Yaron uses one in his ageing process and I've seen pics of the results. GO CAREFUL. a second at a time and remember that it will continue to fade for at least a day afterwards. Once the red had started to fade it will continue to accelerate so keep it out of the sun once it's done. Link to comment Share on other sites More sharing options...
krock Posted April 21, 2013 Share Posted April 21, 2013 Its going to take a very long time to fade with direct sunlight. I've heard some people used to leave the guitar in a room with lit cigarettes to simulate the smoke from years of pub gigging. It would yellow the finish on a white guitar but I'm not too sure about red Link to comment Share on other sites More sharing options...
AXE® Posted April 21, 2013 Share Posted April 21, 2013 I'll cover the neck... Make sure you cover the fretboard as well. ;) Link to comment Share on other sites More sharing options...
Hall Posted April 21, 2013 Share Posted April 21, 2013 buy a black light Link to comment Share on other sites More sharing options...
daveinspain Posted April 21, 2013 Author Share Posted April 21, 2013 Yeah well I meant that too... Was sort of included in covering the neck... Link to comment Share on other sites More sharing options...
pippy Posted April 21, 2013 Share Posted April 21, 2013 Find a UV cannon somewhere (local college/university???). Is that also what Dave Johnson uses at Historic Makeovers? P. Link to comment Share on other sites More sharing options...
daveinspain Posted April 21, 2013 Author Share Posted April 21, 2013 Find a UV cannon somewhere (local college/university???). You can hit it with years worth of sun in seconds. The great Gil Yaron uses one in his ageing process and I've seen pics of the results. GO CAREFUL. a second at a time and remember that it will continue to fade for at least a day afterwards. Once the red had started to fade it will continue to accelerate so keep it out of the sun once it's done. How much time should I leave it exposed to a UV cannon? Link to comment Share on other sites More sharing options...
AXE® Posted April 21, 2013 Share Posted April 21, 2013 At Earth's distance from the Sun, the solar constant is about 1400Watt per square meter, or 1400 Joule per square meter per second. But this is for a direction perpendicular to the sun rays. Therefore, you have to multiply it by the angle of incidence; for example at high noon, you have to multiply this by the cosine of the place's latitude. Link to comment Share on other sites More sharing options...
Guest Farnsbarns Posted April 21, 2013 Share Posted April 21, 2013 How much time should I leave it exposed to a UV cannon? Depends on the power. Talking seconds rather than minutes though. Interestingly, my 11 R8 is fading surprisingly quick given that it lives in a stand in a room that sees very little sun. Is that also what Dave Johnson uses at Historic Makeovers? P. No idea. Sorry. Link to comment Share on other sites More sharing options...
daveinspain Posted April 21, 2013 Author Share Posted April 21, 2013 At Earth's distance from the Sun, the solar constant is about 1400Watt per square meter, or 1400 Joule per square meter per second. But this is for a direction perpendicular to the sun rays. Therefore, you have to multiply it by the angle of incidence; for example at high noon, you have to multiply this by the cosine of the place's latitude. AXE® you really done have to do that, we know you are a genius already.... Link to comment Share on other sites More sharing options...
kidblast Posted April 22, 2013 Share Posted April 22, 2013 At Earth's distance from the Sun, the solar constant is about 1400Watt per square meter, or 1400 Joule per square meter per second. But this is for a direction perpendicular to the sun rays. Therefore, you have to multiply it by the angle of incidence; for example at high noon, you have to multiply this by the cosine of the place's latitude. =D> =D> =D> =D> =D> Link to comment Share on other sites More sharing options...
Versatile Posted April 22, 2013 Share Posted April 22, 2013 At Earth's distance from the Sun, the solar constant is about 1400Watt per square meter, or 1400 Joule per square meter per second. But this is for a direction perpendicular to the sun rays. Therefore, you have to multiply it by the angle of incidence; for example at high noon, you have to multiply this by the cosine of the place's latitude. Thanks I'll get straight on with it... Taxi...!! V Link to comment Share on other sites More sharing options...
krock Posted April 23, 2013 Share Posted April 23, 2013 At Earth's distance from the Sun, the solar constant is about 1400Watt per square meter, or 1400 Joule per square meter per second. But this is for a direction perpendicular to the sun rays. Therefore, you have to multiply it by the angle of incidence; for example at high noon, you have to multiply this by the cosine of the place's latitude. 1.361 kilowatts per square meter (kW/m²) Link to comment Share on other sites More sharing options...
rocketman Posted April 23, 2013 Share Posted April 23, 2013 Have Neo take it to work with him at the nuclear plant. Link to comment Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.