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DC200

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Hello all, hope this finds you all well, and please excuse some of my southern slang.  I am a retired fella and have been into electronics since the Air Force days. Been a guitarist for years and finally decided to dig into tube amps and some design tinkering. I came across Charles R. Couches writings and have been going through those. Along the way of finding his book I stumbled across this site which has a thread from some years ago which I hope means some one on here is following it also. I bring this up because I am hoping to find an answer to a question I have on a calculation he made  on page 66 ;  Iq = Imax / p = 0.318 x Imax .  Since we've established Imax as 0.370 amperes,  then Iq = 0.318 x 0.37 = .118 amperes or 118 milliamps. The problem for me is the variable "p", where does this come from? Thanks for any and all feedback.

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51 minutes ago, DC200 said:

Hello all, hope this finds you all well, and please excuse some of my southern slang.  I am a retired fella and have been into electronics since the Air Force days. Been a guitarist for years and finally decided to dig into tube amps and some design tinkering. I came across Charles R. Couches writings and have been going through those. Along the way of finding his book I stumbled across this site which has a thread from some years ago which I hope means some one on here is following it also. I bring this up because I am hoping to find an answer to a question I have on a calculation he made  on page 66 ;  Iq = Imax / p = 0.318 x Imax .  Since we've established Imax as 0.370 amperes,  then Iq = 0.318 x 0.37 = .118 amperes or 118 milliamps. The problem for me is the variable "p", where does this come from? Thanks for any and all feedback.

I had so much electrical and electronic theory shoved in my head over thirty years ago when I joined The Navy. All those damn formulas for solving inductive reactance and capacitive reactance and Ohm's Law.

As for the variable, no clue, I now just fix electrical stuff that breaks where I work.

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